Radioactive substances decay over time. A certain radioactive substance has a half-life of 4 days, i.e. after 4 days only half of the original amount of substance is present.
Use the following formula;
f(t)=b*a^t,
1/2*b=b*a^t
I already have the following;
Growth factor, a=0.841
b = the initial factor
1/2*b = the half of the initial factor
Question;
c) What fraction of the initial amount of substance is still present after 2,3,4,6,8,10 days? (Prepare a table)
I don’t know if the screenshot with the problem in German will help you.
As far as I am aware, I have to replace the t in the given formula with the number of days, however I am not sure. As I am not sure as to how to make the table.